The Birthday Paradox is a famous problem in probability theory. To solve it, we will first calculate the probability of no two people sharing the same birthday, and then look for the complement probability of at least two people sharing the same birthday.
Assuming there are 365 days in a year (ignoring leap years), we know the probability of the first personβs birthday is 1 since they are the first one in the room.
For the second person not to share their birthday with the first person, there are 364 free days. Therefore, the probability for them not having the same birthday as the first person is $\frac{364}{365}$.
For the third person not to share their birthday with the first and the second person, there are 363 free days. So the probability for them not having the same birthday as anyone else in the room is $\frac{363}{365}$.
Notice the pattern? We can continue similarly for the N people. Then, the probability of no two people sharing the same birthday can be written as:
$$P(\text{no same bday}) = \frac{365}{365} * \frac{364}{365} * \frac{363}{365} * \cdots * \frac{365 - N + 1}{365}$$
Now, we are interested in the probability of at least two people sharing the same birthday, which is the complement of the probability of no two people sharing the same birthday:
P(same bday)β=β1β
ββ
P(no same bday)
We want this probability to be greater than 50%:
P(same bday)β>β0.5
Plug in the expression for P(no same bday):
$$1 - \frac{365}{365} * \frac{364}{365} * \frac{363}{365} * \cdots * \frac{365 - N + 1}{365} > 0.5$$
Now, letβs solve for N.
There is no analytical way to solve for N directly, so we have to calculate it numerically. We can write a simple script or use a spreadsheet to do so. By doing this, we find that the minimum value of N that makes this inequality true is Nβ=β23. Hereβs a more detailed calculation:
$$P(\text{same bday}) = 1 - \frac{365!}{365^N(365-N)!}$$
Trying out different values of N:
- For Nβ=β22, P(same bday)βββ0.475
- For Nβ=β23, P(same bday)βββ0.507
So, the minimum value of N is 23, and thatβs when the probability of at least two people having the same birthday is slightly greater than 50