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Wall Street Quant · Puzzles & Problems · question 15 of 155

If the weights of five people are 50, 60, 70, 80, and 90 kg, what is the standard deviation of their weights?

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To compute the standard deviation of a set of numbers, follow these steps:

1. Compute the mean (average) of the numbers.

2. Subtract the mean and square the result for each number.

3. Compute the mean of the squared differences.

4. Take the square root of the mean of squared differences.

Let’s apply these steps to compute the standard deviation of the given weights:

Weights: wi = [50, 60, 70, 80, 90]

1. Compute the mean (average) of the weights:

$\bar{w} = \frac{1}{n} \sum_{i=1}^{n} w_i = \frac{50 + 60 + 70 + 80 + 90}{5} = \frac{350}{5} = 70$

2. Subtract the mean and square the result for each weight:


$$\begin{aligned} (w_i - \bar{w})^2 &= [(50-70)^2, (60-70)^2, (70-70)^2, (80-70)^2, (90-70)^2] \\ &= [400, 100, 0, 100, 400]\end{aligned}$$

3. Compute the mean of the squared differences:

$\text{MSD} = \frac{1}{n} \sum_{i=1}^{n} (w_i - \bar{w})^2 = \frac{400 + 100 + 0 + 100 + 400}{5} = \frac{1000}{5} = 200$

4. Take the square root of the mean of squared differences:

$\text{SD}(\sigma) = \sqrt{\text{MSD}} = \sqrt{200} \approx 14.1421$

The standard deviation of the given weights is approximately 14.1421 kg.

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