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Wall Street Quant · Financial Models · question 113 of 155

Apply Ito’s lemma to the Geometric Brownian Motion formula to derive the Black-Scholes formula.?

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To derive the Black-Scholes formula, we’ll first apply Ito’s Lemma to the Geometric Brownian Motion formula. Then, we’ll use the risk-neutral pricing approach to finally arrive at the Black-Scholes equation.

The Geometric Brownian Motion (GBM) formula for stock price S under the risk-neutral measure is given as:


dSt = rStdt + σStdWt

where:

- St is the stock price at time t

- r is the risk-free interest rate

- σ is the stock price’s volatility

- Wt is a standard Brownian motion under the risk-neutral measure

Let f(t, S) be a twice-differentiable function w.r.t t and S, Ito’s Lemma states that:


$$df(t, S) = \frac{\partial f}{\partial t} dt + \frac{\partial f}{\partial S} dS + \frac{1}{2} \frac{\partial^2 f}{\partial S^2} dS^2$$

Now let’s consider a European call option C = C(t, S) with maturity T and strike price K. We will try to find an f(S, t) = C(S, t). Using Ito’s Lemma and plugging in our GBM formula, for dS we have:


$$dC = \frac{\partial C}{\partial t} dt + \frac{\partial C}{\partial S} dS + \frac{1}{2} \frac{\partial^2 C}{\partial S^2} dS^2$$


$$dC = \frac{\partial C}{\partial t} dt + \frac{\partial C}{\partial S}(rSdt + \sigma SdW) + \frac{1}{2} \frac{\partial^2 C}{\partial S^2} (\sigma^2 S^2 dW^2)$$

Using the fact that dWt2 = dt, we have:


$$dC = \left( \frac{\partial C}{\partial t} + rS\frac{\partial C}{\partial S} + \frac{1}{2}\sigma^2 S^2 \frac{\partial^2 C}{\partial S^2} \right) dt + \sigma S \frac{\partial C}{\partial S_t} dW_t$$

Now, using the risk-neutral pricing for the European call option:


C(t, S) = e − r(T − t)𝔼t[max(STK,0)]

Under the risk-neutral measure, the payoff is discounted at the risk-free rate:


$$\frac{dC(t,S)}{dt} - rC(t, S) = \sigma S \frac{\partial C}{\partial S_t} dW_t$$

Comparing the two equations above (LHS and RHS), we have


$$\frac{\partial C}{\partial t} + rS\frac{\partial C}{\partial S} + \frac{1}{2}\sigma^2 S^2 \frac{\partial^2 C}{\partial S^2} -rC(t, S) = 0$$

This is the famous **Black-Scholes partial differential equation (PDE)**. Next, we need to solve this PDE with the boundary conditions for a European call option:


C(T, S) = max(S − K, 0)

The solution to this PDE with the given boundary condition is the Black-Scholes formula for a European call option:


C(t, S) = SN(d1) − Ke − r(T − t)N(d2)

where:


$$d_1 = \frac{\ln{\frac{S}{K}} + \left(r + \frac{\sigma^2}{2}\right)(T-t)}{\sigma\sqrt{T-t}}$$


$$d_2 = \frac{\ln{\frac{S}{K}} + \left(r - \frac{\sigma^2}{2}\right)(T-t)}{\sigma\sqrt{T-t}} = d1 - \sigma\sqrt{T-t}$$

and N(x) is the cumulative distribution function of the standard normal distribution.

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