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MongoDB · Intermediate · question 26 of 100

How do you create and drop a unique index in MongoDB?

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In MongoDB, an index is a data structure that improves the speed of data retrieval operations. As its name implies, a unique index ensures that the indexed field or fields contain unique values. This means that no two documents in the collection can have the same value(s) for the fields indexed with a unique index.

To create a unique index in MongoDB, you can use the ‘createIndex()‘ method on the collection object. The syntax of this method is as follows:

db.collection.createIndex(keys, options)

The ‘keys‘ parameter specifies the fields to include in the index and their ordering. It should be an object that maps field names to their sort order (1 for ascending, -1 for descending). For example:

db.myCollection.createIndex({ "name": 1 })

This creates a unique index on the ‘name‘ field in the ‘myCollection‘ collection.

The ‘options‘ parameter is an optional object that can be used to specify additional options for the index. One of the options is ‘unique‘, which should be set to ‘true‘ to create a unique index:

db.myCollection.createIndex({ "email": 1 }, { unique: true })

This creates a unique index on the ‘email‘ field in the ‘myCollection‘ collection.

To drop a unique index in MongoDB, you can use the ‘dropIndex()‘ method on the collection object. The syntax of this method is as follows:

db.collection.dropIndex(index)

The ‘index‘ parameter specifies the index to drop. It should be a string that identifies the index by name or an object that specifies the index keys. For example:

db.myCollection.dropIndex("name_1")

This drops the unique index on the ‘name‘ field in the ‘myCollection‘ collection.

Note that when you drop an index, you cannot undo the operation. The index and its metadata are permanently removed from the collection.

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